Can a client add a freelancer to the client's team if the freelancer has a contract with the client?

[#1]

I have a client who wants to add me to her team to help manage other freelancers. Is it possible to do this while I have an active contract as a freelancer for that client? The client indicates she has already added me to her team, but I do not see anything in my account indicating I am on her team, so I suspect the system might not allow this since I have a current contract with this client as a freelancer.

[#2]

Hi Nathan,

Thank you for your message. Yes, Clients can add hired Freelancers to their teams. When you are added to a new team, you can access the team page by clicking your photo on the top right of your Upwork page. 

Thank you,

Pradeep

[#3]

I don't see an option to access teh team page when I click my profile. All I see is my own profile. My client confirmed that she added me to her team, so I'm not sure what's going wrong here.

[#4]

Sorry to hear that, Nathan. Could you please request the Client to contact us directly so that we can check their account and assist further with the issue? 

Thank you,

Pradeep

[#5]

OK. I have reached out to her so that she can contact you directly. In the meantime, it does appear that it might be an issue with my account. I am getting notifications about contracts that I should be able to see as a member of her team. But I only have my freelancer and my client account listed when I click my picture.

[#6]

Hi Nathan, 

I was unable to identify the contract you're referring to. Could you please share the contract ID so that I can investigate this further, and escalate this to the team (if needed)?

[#7]

The contract ID is 31958726.

[#8 · Accepted solution]

Hi Nathan,

Thank you for sharing the contract ID. I shared your report with our team and one of our agents will reach out to you using a support ticket to assist you further. You can access your support tickets here .

Thank you,

Pradeep

[#9]

Try logging out, clearing your browser's cache/cookies, then logging back in.

[#10]

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