Sep 17, 2015 09:43:30 AM by Koen J
Sep 17, 2015 09:43:30 AM by Koen J
I have read this post.
https://support.upwork.com/entries/23103173
And below is where I'm not clear.
(successful contract outcomes - negative contract outcomes) /total outcomes = job success rate
does it make sense? If I finished a job with negative outcome, I get -100%?
I think the below one makes sense.
(total outcomes - negative contract outcomes) /total outcomes = job success rate
I'm not that great in Math, so forgive me if I'm wrong.
Sep 17, 2015 12:50:51 PM by Dawn L
@Koen J wrote:I have read this post.
https://support.upwork.com/entries/23103173
And below is where I'm not clear.
(successful contract outcomes - negative contract outcomes) /total outcomes = job success rate
does it make sense? If I finished a job with negative outcome, I get -100%?
I'm not the greatest at math either (just ask my husband! LOL!) but the way I understand it is like this:
(successful contracts - unsuccessful contracts) / total contracts
So, for instance, if you have 15 successfully completed contracts, and 3 unsuccessfully completed contracts (or negative feedback) for a total of 18 total contracts, the JSS would be calculated like this:
(15-3) / 18 = JSS%
Again, I could be completely wrong on this, and I am truly horrible with math, but this is how I understand it lol.
Someone please correct me if I'm misunderstanding this lol.
Sep 17, 2015 05:20:31 PM Edited Sep 17, 2015 05:24:26 PM by Vadivelan R
@Koen
You are right!! I felt the same when I first read that entry sometime back.
Lets say, I did two jobs, one success and the other ends in failure. My JSS should be 50% right? According to their calculation:
JSS = ( Success - failure ) / Total Jobs
JSS = (1-1)/2 * 100 = 0% ??
Lets assume I failed both jobs:
JSS = (0-2)/2 * 100 = -100% ??
It should be, as you said:
JSS = ( Total Jobs - Failures / 2 ) * 100
( 1 success, 1 failure ) JSS = ( 2-1 / 2 ) * 100 = 50%
( both failure ) JSS = ( 2-2 / 2 ) * 100 = 0%
I think that they implemented correctly, but not properly explained in that article.
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